practice set 3.5
(Q1)
= ∆XYZ~ ∆LMN
/_X=/_L .....(corresponding angles
/_Y=/_M of similar triangle)
/_Z=/_N
XY/LM=YZ/MN=XZ/LN
....(corresponding sides of similar triangle)
(Q2)
= XY =4 CM , YZ=6 CM, XZ=5 CM,
PQ =8 CM
∆XYZ ~ ∆PQR
XY/PQ = YZ/QR = XZ/PR
......(corresponding sides of similar triangle)
* 4/8= 6/QR =5/PR .....(1)
*4/8 = 6/QR ....[FROM (1)]
QR*4=8*6
*QR= 8*6/4 = 2*6/1
*QR =12CM
4/8=5/PR
......[FROM (1)]
* 4*PR=8*5
* PR = 8*5/4 = 2*5/1
* PR = 10 CM
PR = 12 CM , PR = 10 CM
(Q3)
= ∆ABC ~ ∆PQR
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